log[3](2x-5)-log[3](x+1)=2

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Solution for log[3](2x-5)-log[3](x+1)=2 equation:


Simplifying
log[3](2x + -5) + -1log[3](x + 1) = 2

Reorder the terms:
glo * 3(-5 + 2x) + -1log[3](x + 1) = 2

Reorder the terms for easier multiplication:
3glo(-5 + 2x) + -1log[3](x + 1) = 2
(-5 * 3glo + 2x * 3glo) + -1log[3](x + 1) = 2
(-15glo + 6glox) + -1log[3](x + 1) = 2

Reorder the terms:
-15glo + 6glox + -1glo * 3(1 + x) = 2

Reorder the terms for easier multiplication:
-15glo + 6glox + -1 * 3glo(1 + x) = 2

Multiply -1 * 3
-15glo + 6glox + -3glo(1 + x) = 2
-15glo + 6glox + (1 * -3glo + x * -3glo) = 2
-15glo + 6glox + (-3glo + -3glox) = 2

Reorder the terms:
-15glo + -3glo + 6glox + -3glox = 2

Combine like terms: -15glo + -3glo = -18glo
-18glo + 6glox + -3glox = 2

Combine like terms: 6glox + -3glox = 3glox
-18glo + 3glox = 2

Solving
-18glo + 3glox = 2

Solving for variable 'g'.

Move all terms containing g to the left, all other terms to the right.

Reorder the terms:
-2 + -18glo + 3glox = 2 + -2

Combine like terms: 2 + -2 = 0
-2 + -18glo + 3glox = 0

The solution to this equation could not be determined.

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